please help me with this problem....

Question

I am having a hard time trying to determine the slope intercept form of an equation of a line that passes through the points (6, -2) and has a y - intercept of -2. can you please explaine steps-by-steps.

Answer 1

Given coordinate pair passes though required line.

And required line y intercept is -2.

So the line crosses the y axis at ( 0 , -2)

Equation of a line through the two points is

y + 2 = 0 (x-6)

y + 2 = 0

Subtract 2 from each side.

y  = -2

Above line is parallel to x  - axis.

Slope of above line is 0.

Slope intercept form of a line y = mx.

Required line equation  y  = -2.

Comments

Slope-intercept form line equation is y = mx + b, where m is slope and b is y-intercept.

Answer 2

Slope-intercept form line equation is y = mx + b, where m is slope and b is y-intercept.

The point is (6, - 2) and the y - intercept is - 2.

y - intercept is - 2.

⇒ b = - 2.

Now, the line equation is y = mx - 2.

Find the slope by substituting the point in the line equation say (x, y) = (6, - 2).

- 2 = m(6) - 2

6m = - 2 + 2

m = 0/6

⇒ m = 0.

The line equation in slope - intercept - form is y = (0)x - 2.