Find the derivative of

Question

 

y = cosx / 3x?

Answer 1

y=cosx/3x

Recall the quotient rule d/dx(f(x)/g(x))= [ f'(x)·g(x) - f(x)·g'(x) ] / g²(x)

Here f(x) = cosx ;g(x) = 3x

f'(x) = -sinx;g'(x) = 3

dy/dx=(-sinx)(3x)-(cosx)(3)/(3x)^2

           =-3xsinx-3cosx/9x^2

        = -xsinx-cosx/3x^2

The derivative of the given function is -xsinx-cosx/3x^2

Hope that helps u

Comments

The function .

To find the derivative of y ,

Apply  quotient rule : .

 

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