Particle physics homework, please help?

Question

A proton is accelerated through a voltage of 248 kV. 

a) Calculate the energy of the proton in electron volt and in Joule. 

b) Assuming that the mass of the proton remains the same as its rest mass, calculate the speed of the photon. 

c)The proton is curved by a magnetic field of 1.5 Telsa. Calculate the radius of curvature of its path. 

Please help thank you!!!

 

 

Answer 1

Electron volt is the unit of energy an elementary charge (such as a proton) gets from being accelerated by 1 V.

Therefore 248*10^3 eV for 248kV

Calculate energy in J

K=248*10^3*1.6*10^-19

   =396.8*10^-19 J

b)

K=(1/2)mv^2

v=sqrt(2k/m)

  =sqrt((2*396.8*10^-19)/1.67*10^-27)

  =218^10^3 m/s

c)

r=mv/qB

  =1.67*10^-27*218*10^3/1.6*10^-19*1.5*10^-4

  =15.17 m