Trigonometry!!!!!!!!!!!!!

Question

If the sine of an acute angle is 3/5, what is the cosine of that angle?

Answer 1

sine = opposite side of right triangle divided by hypotenuse.

cosine = adjacent side of right triangle divided by hypotenuse.

You were given sinx = 3/5, which tells me that the hypotenuse is 5 and the opposite side is 3.

We use the Pythagorean Theorem from geometry to find the adjacent side.

Let A = adjacent side.

(3)² + A² = 5²

9 + A² = 25

Subtract 9 from each side.

A² = 16

Taking the square root of both sides, we get A = 4.

Like I said before, cosine = adjacent side of right triangle divided by hypotenuse.

Then cosx = 4/5.