Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

807,724 users

Geometry Circle??

0 votes

A 36 degree arc of circle C is 24π units long. Circumference and and the area of the circle

asked Jun 17, 2014 in GEOMETRY by anonymous

2 Answers

0 votes

Arc length = (m /360)2πr.

Where m is measure of the central angle or arc, and

r is the circumference of the entire circle.

  • From the given data :

Arc length = 24π units.

measure of the central angle or arc (m) = 36 degrees.

Substitute the values arc length = 24π and m = 36 in Arc length = (m /360)2πr.

24π  = (36 /360)2πr.

Circumference of the circle (2πr) = 24π * (360/36)

= 24π * 10

= 240π.

Circumference of the circle (2πr) = 240π units.


 

  • θ = 0.2π radians

radius (r ) = (arc length)/θ.

Substitute the values of arc length = 24π and θ = 0.2π in = (arc length)/θ.

r = 24π/(0.2π)

= 120 units
Area of the circle (A) = πr ².

Substitute the values π = 3.14 and r = 120 in A = πr ².

A = (3.14) * (120)²

= 3.14 * 14400

≅ 45,239 square units.

Area of the circle is 45,239 square units.

answered Jun 17, 2014 by lilly Expert
0 votes

The formula for the length of the arc = 2πr(C/360), where C  is the central angle of the arc in degrees, r  is the radius of the arc and π  is pi, 22/7 (approximately 3.142).

The formula for the circumference of the circle is 2πr units and the area of the circle is πr2.

The angle is 36 degrees and length of the arc 24π units.

Length of the arc = 2πr(C/360).

24π = 2πr(36/360)

240π = 2πr

240(22/7) = 2πr

754.29 ≅ 2πr.

The circumference of the circle is 2πr = 240π and solve for r.

r = 120 units.

The area of the circle is πr2 = π(120)2 = (22/7)(14400) ≅ 45257 units2.

The circumference of the circle is 754.29 units and the area of the circle is 45257 square units.

answered Jun 17, 2014 by casacop Expert

Related questions

...