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Calc w/ Parametric Curves HELP?

0 votes

I keep getting -1 as my answer, but that answer is not one of the possible options... Please show your work on how to solve. Thank you!!

asked Jul 20, 2014 in CALCULUS by anonymous

1 Answer

0 votes

x = 5sint

Apply derivative to each side.

d/dt = d/dt (5sint) = 5cost.

y = 5cost

Apply derivative to each side.

dy /dt = d/dt (5cos) = -5sint.

dy / dx = (dy /d) / (d/d)

           = -5sint / 5cost

           = - tant

---------------------

x = 5sint

sint =x/5

t = sin-1 (x/5 )

dy / dx =- tan(sin-1 (x/5 ))

               =-(x/5)/√(1-(x/5)2)                                          (Since tan(sin-1 (x)) =x/√ (1-x2))

                  =-x/√(25-x2)

Take the derivative both sides

d2y / dx2  =-(d/dx)(x/√(25-x2))

                 =-(√(25-x2)(1)-x(-1/(2√(25-x2))(2x))/(25-x2)

                 =-(√(25-x2)-x2(-1/(√(25-x2))/(25-x2)

                  =-((25-x2)+x2)/(25-x2)3/2

                     =-25/(25-x2)3/2

At t = 3π/4

x= 5sin3π/4 =5/√2

d2y / dx2  =-25/(25-x2)3/2

                    =-25/(25-(5/√2)2)3/2

                     =-25/(25-(25/2))3/2

                      =-25/(25/2)3/2

                       =-25*23/2/125

                 =-2√2/5

Option (c) is correct.

 

answered Jul 24, 2014 by joly Scholar
edited Jul 24, 2014 by bradely

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