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Ellipses

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Write an equation for an ellipse with foci (0, +4) and co-vertices (+ 2, 0).

asked Aug 15, 2014 in PRECALCULUS by swatttts Pupil

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The foci of the ellipse (0, ± 4) and co-vertices (± 2, 0).

To find the equation of ellipse, first find major axis is vertical or horizontal, and next find the values of a, b, h and k.

Since the x - coordinate is same in the foci, the major axis is vertical, then the equation of ellipse is (x - h)2/b2 + (y - k)2/a2 = 1.


Find the value of b :

Here length of the major axis = the distance between two co-vertices (2, 0) and (-2, 0).

2b = √[ (x2 - x1)2 + (y2 - y1)2 ]

2b = √[ (2 - (-2))2 + ( 0 - 0)2 ]

2b = √[4]

2b = 2

b = 1.

 

Find the center (h, k) :

The center of the ellipse lies at the midpoint of its co-vertices or foci.

The center of the ellipse = the midpoint of its co-vertices (0, 2) and (0, -2).

So, the center (h, k) = [ (x₁ + x₂)/2, (y₁ + y₂)/2 ] = [ (0 + 0)/2, (- 2 + 2)/2 ] = (0, 0).

 

Find the value of a :

c2 = a2 - b2

(4)2 = a2 - (1)2

16 = a2 - 1

17 = a2 .

 

The equation of ellipse is x2/17 + y2/1 = 1.

 

answered Aug 15, 2014 by casacop Expert
selected Aug 15, 2014 by swatttts
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