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What is the equation of the ellipse with vertices at (-25, 0), (25, 0) and co-vertices (0, -15), (0, 15)?

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What is the equation of the ellipse with vertices at (-25, 0), (25, 0) and co-vertices (0, -15), (0, 15)?
A. x squared divided by 625 minus y squared divided by 225 equals 1
B. x squared divided by 225 plus y squared divided by 625 equals 1
C. x squared divided by 225 minus y squared divided by 625 equals 1
D. x squared divided by 625 plus y squared divided by 225 equals 1
 

 

asked Sep 8, 2014 in ALGEBRA 2 by tonymate Pupil

1 Answer

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Best answer

The vertices lie on the line y=0 which is horizontal. This means the major axis is the x-axis.

The horizontal ellipse equation is x2/a2 + y2/b2 = 1

Vertices : (± a, 0) = (± 25, 0)  ----->   a = 25.

Co-vertices : (0, ±b) = (0, ± 15)  ----->   b = 15.

Substitute a = 25 and b = 15 in the ellipse equation.

x2/(25)2 + y2/(15)2 = 1

x2/625 + y2/225 = 1

The option D is correct.

answered Sep 9, 2014 by casacop Expert
edited Sep 9, 2014 by moderator
Please check the updated answer.

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