Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

807,716 users

helpppp! i cant understand this

0 votes
complete the table of values for the quadratic function y=2(x - 3 )^2 - 5. make sure include vertwx and 2  points on each side of the vertwx. draw and accurate graph of this quadratic function then answer the following:

a.  what are the coordinates of the vertex. label the vertex in graph

b. what is the equation of the axis of symmetry? draw and label the axis of symmetry on graph using dotted line

c. label the x-intercepts on graph

d. label the y intercepts on graph and show how to find the coordinates of the y intercepts methematically.
asked Oct 13, 2014 in CALCULUS by anonymous

1 Answer

0 votes
 
Best answer

The quadratic equation is y = 2(x - 3)^2 - 5.

Compare the equation y = 2(x - 3)^2 - 5 with standard form of parabola equation y = a(x - h)^2 + k.

a = 2, h = 3 and k = -5.

Vertex = (h, k) = (3, - 5).

Axis of symmetry : x = h = 3.

To find x-intercept, substitute y = 0 in the original function y = 2(x - 3)^2 - 5.

0 = 2(x - 3)^2 - 5

2(x - 3)^2 - 5 = 0

(x - 3)^2 = 5/2

x = 3 ± √(5/2).

To find y-intercept, substitute x = 0 in the original function y = 2(x - 3)^2 - 5.

y = 2(0 - 3)^2 - 5

y = 13.

Make the table :

x

y = 2(x - 3)^2 - 5

y

(x, y)

1

y = 2(1 - 3)^2 – 5 = 3

3

(1, 3)

2

y = 2(2 - 3)^2 – 5 = -3

-3

(2, -3)

4

y = 2(4 - 3)^2 – 5 = -3

-3

(4, -3)

5

y = 2(5 - 3)^2 – 5 = 3

3

(5, 3)

6

y = 2(6 - 3)^2 – 5 = 13

13

(6, 13)

Graph :

answered Oct 15, 2014 by casacop Expert

Related questions

asked Nov 17, 2014 in CALCULUS by anonymous
asked Oct 21, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 15, 2014 in CALCULUS by anonymous
asked Dec 9, 2014 in PRECALCULUS by anonymous
asked Oct 31, 2017 in CALCULUS by anonymous
asked Jan 29, 2015 in CALCULUS by anonymous
asked Nov 4, 2014 in CALCULUS by anonymous
...