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Tan^-1[tan(2pi/3)]

0 votes

How do I solve this?

inverse-function

asked Oct 21, 2014 in TRIGONOMETRY by anonymous

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1 Answer

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The trigonometricexpression is tan^-1[tan(2π/3)].

The value of tan(2π/3) = tan(π - π/3) = - tan(π/3) = - √3.

tan^-1[tan(2π/3)] = tan^-1(- √3) = - tan^-1(√3) = - (π/3).

answered Oct 21, 2014 by casacop Expert

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