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Find equation of loci for:

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arg(z+3)=pi/4?

asked Oct 22, 2014 in PRECALCULUS by anonymous

1 Answer

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arz(z + 3) = π/4.

arz(x + iy + 3) = π/4.

arz[(x + 3) + iy] = π/4.

We know that θ = arg z = tan-1(y/x).

tan-1[y/(x + 3)] = π/4.

y/(x + 3) = tan(π/4)

y/(x + 3) = 1

y = x + 3

The locus is y = x + 3.

 

answered Oct 22, 2014 by casacop Expert
edited Oct 22, 2014 by casacop

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