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0 votes

asked Oct 22, 2014 in PRECALCULUS by Baruchqa Pupil

3 Answers

+2 votes

2)

a)

d/dx (2x³ - x3/2 + (4/√x))

= d/dx (2x³ - x3/2 + (4x-1/2)

=2d/dx (x³) - d/dx (x3/2)+4 d/dx(x-1/2)

=2(3x²) - (3/2)(x3/2-1)+4 (-1/2) d/dx(x-1/2-1)

=6x² - (3/2)(x1/2) - 2 x-3/2

answered Oct 23, 2014 by bradely Mentor
+1 vote

2)

c)

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Apply formula  : image

 

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answered Oct 24, 2014 by lilly Expert
apply the formula, please explain how you get from step 2 to 3. where tje 3 and 1 come from

Explaination from step 2 to 3 :

Here Consider

U = 3x - 4

V = x + 2

image

Then substitute in formula :

Substitute U = 3x - 4 and V = x + 2

Explaination of 3 and 1 come from :

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+1 vote

2)

b)

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Apply formula aman = am+n

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Apply formula  : (d/dx) (xn) = nxn-1

3(5/2)x(5/2)-1 - (3/2)(-3/2)x(-3/2)-1

(15/2)x(3/2) + (9/4)x(-5/2)

The solution is (15/2)x(3/2) + (9/4)x(-5/2)

answered Oct 24, 2014 by lilly Expert

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