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Use the Chain Rule to find the indicated partial derivatives.

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z = x^4 + x^2y, x=s+2t −u, y =stu^2; ∂z/∂s ∂z/∂t ∂z/∂u when s = 3, t = 4, u = 5?

asked Oct 26, 2014 in CALCULUS by anonymous

3 Answers

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(1).

The function are z = x4 + x2y, x = s+2t-u, y = stu2, and the values are s = 3, t = 4, u = 5.

Substitute x = s+2t-u and y = stu2 in the function z = x4 + x2y.

z = (s+2t-u)4 + (s+2t-u)2(stu2)

Partial differentiate with respect to s to the above function.

∂z/∂s = (∂/∂s)[(s+2t-u)4 + (s+2t-u)2(stu2)]

∂z/∂s = 4(s+2t-u)3 + [(s+2t-u)2(tu2) + 2(s+2t-u)(stu2)]

Substitute s = 3, t = 4 and u = 5 in the above function.

∂z/∂s = 4[3+2(4)-5]3 + [3+2(4)-5]2(4 * 52) + 2[3+2(4)-5](3 * 4 * 52)

∂z/∂s = 864 + 3600 + 3600

∂z/∂s = 8064

answered Oct 26, 2014 by casacop Expert
0 votes

(2).

The function are z = x4 + x2y, x = s+2t-u, y = stu2, and the values are s = 3, t = 4, u = 5.

Substitute x = s+2t-u and y = stu2 in the function z = x4 + x2y.

z = (s+2t-u)4 + (s+2t-u)2(stu2)

Partial differentiate with respect to t to the above function.

∂z/∂t = (∂/∂t)[(s+2t-u)4 + (s+2t-u)2(stu2)]

∂z/∂t = 8(s+2t-u)3 + [(s+2t-u)2(su2) + 4(s+2t-u)(stu2)]

Substitute s = 3, t = 4 and u = 5 in the above function.

∂z/∂t = 8[3+2(4)-5]3 + [3+2(4)-5]2(3 * 52) + 4[3+2(4)-5](3 * 4 * 52)

∂z/∂t = 1728 + 2700 + 7200

∂z/∂t = 11628.

answered Oct 26, 2014 by casacop Expert
edited Oct 26, 2014 by casacop
0 votes

(3).

The function are z = x4 + x2y, x = s+2t-u, y = stu2, and the values are s = 3, t = 4, u = 5.

Substitute x = s+2t-u and y = stu2 in the function z = x4 + x2y.

z = (s+2t-u)4 + (s+2t-u)2(stu2)

Partial differentiate with respect to u to the above function.

∂z/∂u = (∂/∂u)[(s+2t-u)4 + (s+2t-u)2(stu2)]

∂z/∂u = -4(s+2t-u)3 + [2(s+2t-u)2(stu) - 2(s+2t-u)(stu2)]

Substitute s = 3, t = 4 and u = 5 in the above function.

∂z/∂u = -4[3+2(4)-5]3 + 2[3+2(4)-5]2(3 * 4 * 5) - 2[3+2(4)-5](3 * 4 * 52)

∂z/∂u = - 864 + 4320 - 3600

∂z/∂u = -144.

answered Oct 26, 2014 by casacop Expert

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