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The slop of the tangent line to the parabola

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y = 3x^2 - 6x + 4 a the point where x = 3 is ___?

slope-of-tangent-line

asked Nov 6, 2014 in PRECALCULUS by anonymous

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1 Answer

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The function y = 3x² - 6x + 4

Differentiating on each side with respect to x .

y' = 6x - 6

Substitute the value x = 3 in above equation.

y' = 6(3) - 6

y' = 18 - 6

y' = 12

This is the slope of tangent line to the y = 3x² - 6x + 4 at x = 3.

Slope of tangent line = 12.

answered Nov 6, 2014 by david Expert

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