What are the first three derivatives of

Question

ln (e^x) + 5.?

Answer 1

ln (e^x) + 5

Rewrite the function as logarithm and exponential get cancel .

x + 5

Apply derivative with respect to x .

= d/dx [​x + 5]

= d/dx [x] + d/dx (5)

= 1 + 0                  [ derivative of  xⁿ = n x^n-1 ]

So the first derivative of the function ln (e^x) + 5 is 1 .