Calculus Help?!?!?

Question

Suppose f(2)=3, g(2)=5, f'(2)=-2, g'(2)=4, and f'(5)=11 
If h(x)=f(x) g(x), find h'(2) 
Please help! What do you do with the two f'?

Answer 1

The function is h(x) = f(x)*g(x)

The values of f(2) = 3, g(2) = 5, f'(2) = -2 and g'(2) = 4

Differentiate with respect to x.

h'(x) = f'(x)g(x) + g'(x)f(x)

h'(2) = f'(2)g(2) + g'(2)f(2)

h'(2) = -2*5 + 4 * 3

h'(2) = -10 + 12

h'(2) = 2.

Therefore the h'(2) is 2.