Physics Homework Help!?

Question

What is the thermal energy required to convert 100g of ice at 0'C to water at 20'C? 

(Specific heat capacity of water is 4200Jkg^-1C^-1 and the specific latent heat of fusion for ice is 3.34x10^-5kg^-1)

Answer 1

Mass of the ice is 100 g = 0.1 kg.

Ice Melts at 0°C to 20°C.

Specific Heat of water is 4200 J / kg °C

Specific Latent Heat of Fusion of Ice is 3.34 * 10^5 J/kg

First calculate energy to melt 100g of ice at 0°C usig latent heat of melting.

Q1 = m * L

Q1 = 0.1 * 3.34 * 10^5

Q1 = 3.34 * 10^4 J

Second calculate energy to rise the temperature of 100g of water from 0°C to 20°C using heat capacity of water

Q2 = m * C * ΔT

Q2 = 0.1 * 4200 * 20

Q2 = 8400 J.

Therefore total Heat  = Q1 + Q2

Q = 41800

Q = 41.8 kJ.

Therefore the Total Thermal Energy is 41.8 kJ.