Algebra 2 help pleases help?

Question

3, 6 ,9, 13,4 ,6, 12, 14 ,11, 2, 2,

Find

Mean_____ 

Median ____ 

Mode_____

Answer 1

 Mean

3, 6 ,9, 13,4 ,6, 12, 14 ,11, 2, 2

Arithmetic mean = sum of elements / total number of elements

sum of elements = 3 + 6 + 9 + 13 + 4 + 6 + 12 + 14 + 11 + 2 + 2

sum of elements = 41 + 41

sum of elements = 82

Total number of elements = 11

There fore Arithmetic mean = mean = 82 / 11

Mean = 7.46 (approximately).

Answer 2

Median

3, 6 ,9, 13,4 ,6, 12, 14 ,11, 2, 2

We can rewrite an array then

2, 2, 3, 4, 6 , 6, 9, 11, 12, 13, 14

Median is the middle term of an array

The middle term of an above array is 6

There fore Median = 6

Mediam of above elements is 6.

Answer 3

Mode

3, 6 ,9, 13,4 ,6, 12, 14 ,11, 2, 2,

Mode : The value that appears most

6 is the appears two times

2 is the appears two times

There is "no mode".