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Given that f(x)=x³(5-3x)²

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find f'(2)?

asked Nov 17, 2014 in CALCULUS by anonymous

1 Answer

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f(x) = x³(5-3x)² 

f(x) = x³(25 + 9x² -30x )

f(x) = 25x³ + 9X-30X4

f '(x) = d/dx (25x³ + 9X-30X4)

Apply general power formula that is derivative of  xn = n xn-1

f '(x) = 25*3x² + 9*5X5-1 - 30*4X4-1

 f '(x) = 75x² + 45X- 120X3

so  f '(2) = 75(2)² + 45(2)- 120(2) ⇒75*4 + 45*16 -120*8

                                                            ⇒ 300 +720 - 960

                                                            ⇒1020 - 960 = 60

So   f '(2) =  60 .

answered Nov 18, 2014 by yamin_math Mentor

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