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Integral problem

0 votes

Solve step by step.

asked Dec 3, 2014 in CALCULUS by anonymous

1 Answer

0 votes

The Function is image.

The Hyperbolic sine function is

image

Substitute the value of sinh(x) in the above function.

image

image

Now consider image.

Apply derivative on both sides.

image

Then

image

image

Let us consider

image

image

Comapre the coefficients of u.

A+B = 0

A = -B

Comapre the coefficients of Constants.

A - B = 2

2A = 2

A = 1 then B = -1.

image

image

image

image         (Using the Logarithmic rule image)

Substitute image.

image

image

We know that  image.

image

Therefore image.

answered Dec 3, 2014 by Lucy Mentor
edited Dec 3, 2014 by Lucy
I don't understand the part after substituting u=e^x near the end. After substituting you multiply the exponent by 2 and divide it by 2? How is that then the same as tanh(x) which has e^2x in the numerator and demoninator not e^2(x/2)?

The Standard algebraic expression of Hyperbolic function of tanh(x) is  image.

Now coming to our solution, after substituting image, we get

image

Multiply and divide with 2 in the power of the exponent function.

image

The term image resembles the Standard algebraic expression of Hyperbolic function of tanh(x) where we have x/2 instead of x.

Then we can write image.

Therefore we can write

image

Therefore image.

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