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Solve for x: 4^4x-3 =67?

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Solve for x: 4^4x-3 =67?

logarithmic-expression

asked Apr 20, 2013 in ALGEBRA 2 by linda Scholar

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1 Answer

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4^{4x - 3} = 67

Take logarithm to each side

log4^{4x - 3} = log67

Recall : Logarithm formula loga^x = x loga

(4x -3)log4 = log67

(4x - 3)2log2 = 1.8261

(4x - 3)(2)(0.3010) = 1.8261

4x - 3 = 1.8261 / 0.6020

4x - 3 = 3.03334

4x = 6.03334

x = 1.508335 (Approximately).

answered Apr 23, 2013 by diane Scholar

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