Question

Use implicit differentiation to find an equation of the tangent line to the graph at the given point.

x + y - 1 = ln (x^2 + y^2),          (1, 0)

Answer 1

Step 1:

The equation is and the point is .

The slope of the tangent line is equal to the derivative of the function at .

Apply derivative on each side with respect to .

Step 2:

Slope at the point , Substitute  in .

Point-slope form of line equation .

Substitute point and slope in the above equation.

Tangent line equation is .

Solution:

Tangent line equation is .