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Let f(x)= 6x^2, find fprime(3) using the limit definition of the derivative.

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Let f(x)= 6x^2, find fprime(3) using the limit definition of the derivative. will be slope of the tangent line to the function of x=5?

asked Feb 12, 2015 in CALCULUS by anonymous

1 Answer

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Step 1:

The function is image.

image prime of image means the first derivative of image at image.

First find the derivative of the function using the limit definition of derivative.

Limit definition of derivative: image.

image

Derivative of the function is image.

Step 2:

Now find image prime of 3.

image prime of 3 can be written as image.

Substitute image in the derivative of the function.

image

image prime of 3 is 36.

Step 3:

Find the slope of the tangent line at image.

Slope of the tangent is the derivative of the function at that point.

Substitute image in the derivative of the function.

image

The slope of the tangent line at image is 60.

Solution:

Derivative of the function is image.

image prime of 3 is 36.

The slope of the tangent line at image is 60.

answered Feb 23, 2015 by Lucy Mentor
edited Feb 23, 2015 by Lucy

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