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Solve the initial-value problem.

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Solve the initial-value problem.

asked Feb 18, 2015 in CALCULUS by anonymous

1 Answer

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Step 1 :

The differential equation is image and the initial conditions are .

The auxiliary equation is image.

Find roots of the auxiliary equation.

The roots of the auxiliary equation .

The general solution is

Step 2 :

Substitute the initial condition in equation (1)

Differentiate equation (1) with respect to x.

Substitute the initial condition in above equation.

Step 3 :

Subtract equation (2) from equation (3).

Substitute in equation (2).

Substitute and in equation (1).

The general solution is .

Solution :

The general solution is .

answered Feb 21, 2015 by Thomas Apprentice

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