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Question

In a given experiment, 5.2 moles of pure NOCl was placed in an otherwise empty 2.0-L container. Equilibrium was established by the following reaction:

2NOCL (g) <--> 2 NO (g) + Cl2 (g) K= 1.6 * 10^(-5)

(a) Using numerical values for the concentrations in the Initial row and expressions containing the variable x in both the Change and Equilibrium rows, complete the fol- lowing table summarizing what happens as this reaction reaches equilibrium. Let x 5 the concentration of Cl2 that is present at equilibrium. 

 

	NOCl	NO	Cl2
Initial
Change
Equilibrium 2.6 2 2x

b. Calculate the equilibrium concentrations for all species. 

 

Answer 1

Step 1:

(a)

The equilibrium constant K is 1.6 * 10^-5.

Initially 5.2 moles of NOCl is placed in 2.0 L of container.

Initial amount of NOCl is .

The chemical equation is .

Let x be the concentration of Cl₂.

Then concentration of NO at equilibrium be 2x.

Step 2:

Now complete the give ICE table.

Equilibrium Amount = Initial amount + Change in amount.

(i)

Find the change in amount of NOCl.

From the table, Equilibrium amount of NOCl is .

Initial amount of NOCl is 2.6 M.

Equilibrium Amount = Initial amount + Change in amount.

Change in amount of NOCl is .

(ii)

Find the change in amount of NO.

Initially the amount of NO is 0 M.

Equilibrium Amount of NO is 2x.

Equilibrium Amount = Initial amount + Change in amount.

2x = 0 + Change in amount.

Change in amount of NOCl is 2x.

(iii)

Find the change in amount of Cl₂.

Initially the amount of Cl₂ is 0 M.

Equilibrium Amount of Cl₂ is x.

Equilibrium Amount = Initial amount + Change in amount.

x = 0 + Change in amount.

Change in amount of Cl₂ is x.

Step 3:

Solution:

Answer 2

Step 1:

(b)

The equilibrium constant K  is 1.6 * 10^-5.

The concentrations of [NOCl], [NO] and [Cl₂] is , 2x and x.           [From (a)].

Definition of equilibrium constant:

Equilibrium constant  is the ratio of the concentrations of products to the concentration of reactants.

.

The chemical reaction is .

Solutions of is x = 0.02977, 0.01489+0.026i and 0.01489-0.026i.

Imaginary values are not considered, x = 0.02977

Concentration of [Cl₂] at equilibrium is

Concentration of [NO] at equilibrium is

Concentration of [NOCl] at equilibrium is

Solution:

Concentration of [Cl₂] at equilibrium is

Concentration of [NO] at equilibrium is

Concentration of [NOCl] at equilibrium is