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help?CONTINUITY

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asked Apr 27, 2015 in CALCULUS by anonymous

3 Answers

0 votes

A function  is continuous at , if  then it should satisfy three conditions:

(1)  is defined.

(2)  exists.

(3) .

Observe the graph:

  is discontinuous at , and .

Check the continuity at .

The value of the function at is .

is defined at .

answered Apr 27, 2015 by david Expert
edited Apr 27, 2015 by bradely

Contd..

Left hand limit :

As image tends to -2 from left hand side, approaches to 3.

.

Right hand limit :

As image tends to -2 from right hand side, approaches to 3.

.

As left hand limit and the right hand limits are equal, limit exist.

image is exist.

Hence , .

fails the continuity test condition (3) at .

is discontinuous at .

Solution:

is discontinuous at .

0 votes

Check for the continuity at .

Observe the graph:

The value of the function at is .

is defined at .

Left hand limit :

As image tends to 1 from left hand side, approches to -3.

.

Right hand limit :

As image tends to 1 from right hand side, approches to 4.
.

Since , does not exist.

fails the continuity test conditions (2), (3) at .

 is discontinuous at .

Solution:

 is discontinuous at .

answered Apr 27, 2015 by david Expert
edited Apr 27, 2015 by bradely
0 votes

Check for the continuity at .

The value of the function at is undefined.

is undefined at .

Left hand limit :

As image tends to 4 from left hand side, approaches to image.

.

Right hand limit :

As image tends to 4 from right hand side, approaches to image.

.

Since , does not exist.

fails the continuity test condition (1), (2), (3) at .

is discontinuous at .

Solution:

  is discontinuous at .

  is discontinuous at , and .

answered Apr 27, 2015 by david Expert
edited Apr 27, 2015 by bradely

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