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help? derivative-trig

0 votes

asked May 1, 2015 in CALCULUS by anonymous

2 Answers

0 votes

(7)

Step 1:

The function is image and image.

Slope of the tangent line equation is derivative of the function.

image.

Differentiate on each side with respect to .

image.

Product rule of derivatives : .

image

Substitute image in derivative function.

image

Slope of the tangent line equation is image.

Step 2:

Find the point of tangency.

Substitute image in the function.

image

Tangent point is image.

Find the equation of tangent line.

Point slope form of the line equation : .

Substitute image and image in point slope form of line equation.

image

Tangent line equation is image.

Solution :

Tangent line equation is image.

answered May 1, 2015 by cameron Mentor
edited May 1, 2015 by cameron
0 votes

(8)

Step 1:

The function is .

Differentiate on each side with respect to .

.

Find the critical points.

A critical number of a function is a number in the domain of such that either or does not exist.

Find the critical point by graphing the derivative function.

Graph:

Graph the derivative function .

Observe the graph:

Locate the values of x where the value of the derivative function is zero.

Critical points are and .

answered May 1, 2015 by cameron Mentor
edited May 1, 2015 by cameron

Continued...

Step 2:

The range is .

The test intervals are , , , and .

Therefore the function is increasing on the intervals , and .

The function is decreasing on the intervals and .

Solution:

The function is increasing on the intervals , and  .

The function is decreasing on the intervals and  .

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