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Find dy/dx For Inverse Hyperbolic Functions?

0 votes

Find dy/dx For Inverse Hyperbolic Function

y = sinh^(-1) (cosh2x)

asked Jun 3, 2013 in CALCULUS by anonymous Apprentice

2 Answers

0 votes

y = arcsinh(cosh2x)

Take sinh to each side

sinhy = sinh(arcsinh(cosh2x)

Since sinh and arcsinh are inverse functions

sinhy = cosh2x

Take derivative to each side with respective x

coshy dy / dx = sinh2x (2)

dy / dx = 2sinh2x / coshy.

answered Jun 3, 2013 by diane Scholar
0 votes

The inverse hyperbolic function is y = sinh^(-1) (cosh2x).

image

answered Jul 15, 2014 by casacop Expert

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