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help? sequences?

0 votes

asked Jun 1, 2015 in CALCULUS by anonymous

4 Answers

0 votes

(1)

Step 1:

The sequence is image.

image.

Apply infinite limit on each side.

image.

image

Formula : If  image for image,  the sequence image is divergent.

image

image.

Hence the sequence is divergent and value of the limit is image.

Solution :

The sequence is divergent and value of the limit is image.

answered Jun 1, 2015 by Lucy Mentor
edited Jun 1, 2015 by Lucy
0 votes

(2)

Step 1:

The sequence is image.

image.

Apply infinite limit on each side.

image

image

Formula : If  image for image,  the sequence image is divergent.

Formula :  If image for image, the sequence image is divergent.

image

image.

Hence the sequence is divergent and value of the limit is image.

Solution :

The sequence is divergent.

answered Jun 1, 2015 by Lucy Mentor
edited Jun 1, 2015 by Lucy
0 votes

(3)

Step 1:

The sequence is image.

image.

Apply infinite limit on each side.

image.

First calculate the absolute value of the sequence.

image

Formula : If  image for image,  the sequence image is divergent.

image

image.

Hence the sequence is divergent and value of the limit is image.

Solution :

The sequence is divergent.

answered Jun 1, 2015 by Lucy Mentor
0 votes

(4)

Step 1:

The sequence is image.

image.

Apply infinite limit on each side.

image.

First calculate the absolute value of the sequence.

image

Formula :  If image for image, the sequence image is divergent.

image

image does not exist as it oscillates between image and image.

Hence the sequence is divergent and limit of the sequence does not exist.

Solution :

The sequence is divergent and limit of the sequence does not exist.

answered Jun 1, 2015 by Lucy Mentor

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