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application-integrals [help??

0 votes

asked Jun 2, 2015 in CALCULUS by anonymous

2 Answers

0 votes

3)

Step 1:

The curve equation is  and line is  and .

Area of the shaded region is .

Observe the graph:

Upper line is .

Lower curve is .

Here and

.

Area of the shaded region is  sq-units.

Solution:

Area of the shaded region is sq-units.

answered Jun 2, 2015 by cameron Mentor
0 votes

4)

Step 1:

The curve equations are image and image.

Graph the functions image and image.

Shade the required region.

image

Observe the graph :

Region enclosed by the given curves is between image and image.

Step 2:

Area between the curves and and between and is 

.

Here image and image.

Area of the region , image.

image

image

image

Area of the region is image sq-units.

Solution:

Area of the region is image sq-units.

answered Jun 2, 2015 by cameron Mentor
edited Jun 2, 2015 by cameron

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