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help-convergence?

0 votes

asked Jun 2, 2015 in CALCULUS by anonymous

1 Answer

0 votes

(3)

Step 1:

The series is image.

Integral test :

Suppose image is continuous, positive and decreasing on the interval image then

(i) image is convergent, then the image is also convergent.

(ii) image is divergent, then the image is also divergent.

The function image is continuous, positive and decreasing on the interval image.

image

image

image

image diverges, hence by integral test image also diverges.

The series is divergent.

Solution :

The series is divergent.

answered Jun 2, 2015 by Lucy Mentor
edited Jun 2, 2015 by Lucy

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