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Physics Homework Help?

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A 4.00-kg mass and a 3.00-kg mass are attached to opposite ends of a very light 42.0-cm-long horizontal rod (the figure). The system is rotating at angular speed ω = 5.55 rad/s about a vertical axle at the center of the rod.(Figure 1)

Part A
Determine the kinetic energy KE of the system.

 

Part B
Determine the net force on 4.00 kg mass.
Part C
Determine the net force on 3.00 kg mass.

 

asked Oct 23, 2015 in PHYSICS by anonymous

3 Answers

0 votes

(a)

Step1:

The masses are image and image.

The two masses are attached to a long horizontal rod of length is image.

The angular speed of the system is image.

The kinetic energy is image, where image is the moment of inertia.

The moment of inertial of the system is image.

image.

Substitute image, image and image.

image

image

image kg-m².

Step 2:

Find the kinetic energy of the system.

Substitute image, image in image.

image

image

image

= 4.75 J.

The kinetic energy of the system is 4.75 J.

Solution:

The kinetic energy of the system is 4.75 J.

answered Oct 23, 2015 by Sammi Mentor
0 votes

(b)

The masses are image and image.

The two masses are attached to a long horizontal rod of length is image.

The angular speed of the system is image.

Find the net force on image mass.

The net force on image mass is image.

Substitute image, image and image.

image

image

image

image.

The net force on image mass is image.

answered Oct 23, 2015 by Sammi Mentor
0 votes

(c)

The masses are image and image.

The two masses are attached to a long horizontal rod of length is image.

The angular speed of the system is image.

Find the net force on image mass.

The net force on image mass is image.

Substitute image, image and image.

image

image

image

image.

The net force on image mass is image.

answered Oct 23, 2015 by Sammi Mentor

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