Physics Homework Question?

Question

An ideal gas expands isothermally, performing 4.80×103 J of work in the process.

Part A

Calculate the change in internal energy of the gas.

 

Part B

Calculate the heat absorbed during this expansion.

 

Answer 1

In a isothermal process temeprature is constant.

It means ΔU =0.

change in internal energy of the gas is zero

From the firstlaw of thermodynamics

Q = ΔU + W

    =0 +4.80×10^3

    = 4.80×10^3 J

Answer 2

(a)

For an isothermal process, temperature is constant.

Isothermal process: .

Change in internal energy of the gas is 0.

(b)

Work done

According to the first law of thermodynamics: .

For an isothermal process: .

Heat absorbed during this expansion is