Find the magnitude and direction angle θ, to the nearest tenth of a degree, for the given vector v. v = -4i - 3j

Answer 1

Step 1:

The vector is .

The standard form of the vector is

Magnitude of the vector .

Magnitude of the vector

Magnitude is

Step 2:

The vector is

Direction angle is .

Where .

The vector is lies in IV quadrant, lies in IV quadrant.

The reference angle

Direction angle is

Solution :

Magnitude is

Direction angle is