Find the tangent of the function

Question

y=x^2+2 at x = 1

Answer 1

y=x^2+2

At x = 1

y =(1)^2+2 =3

Calculate the tangent slope.

dy/dx=2x

m=dy/dx|@x=1=2(1)=2

Calculate the tangent.

y-3 =2(x-1)

y-3 =2x-2

2x-y+1=0