Question

What would be the height of a trapezoidal building if, at its base, it measured 80 feet, its roofline measured 40 feet, and the surface area of one side was 7,200 ft2?

Answer 1

Given,

Base (b1) = 80ft.

Roofline (b2) = 40ft

Area of one side (A) = 7200 ft^2.

Area of the Trapezoid

A  =  1/2(b1 + b2) h ------------------>(1)

Substitute b1 = 80, b2 = 40 and A = 7200 in Eq (1)

7200  =  1/2(80 + 40)h

7200 X 2  =  120h

h  =  (7200X 2) / 120

h  = 120 ft.

Answer :

Height of the building is 120 ft.