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Physics practice test. Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Two electrons are passing 20 mm apart.what is the electric repulsive force that they exert on each other?(The valu of k is 9*10^9 N-m^2/c^2)

asked Jul 21, 2013 in CALCULUS by linda Scholar

1 Answer

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Find electric repulsive force using

F=kq1q2/d^2

Here q1 and q2 are  the strengths of electrons,d is distance between electrons and k Coulomb's constant.

strengths of electrons,q1=q2=1.602 x 10-19. C

Substitute ,q1=q2=1.602 x 10-19. C,k=9*10^9 N-m^2/c^2 and d=20 mm

F=(9*10^9)(1.602 x 10-19)(1.602 x 10-19)/(0.02)^2

   =0.5766422350752*10^-24 N

answered Jul 21, 2013 by bradely Mentor

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