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Please help probability

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In 10 tosses of a coin, what is the probability of getting not less than 3 heads and not more than 6 heads?
asked Sep 9, 2013 in PRECALCULUS by mathgirl Apprentice

1 Answer

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probability of getting not less than 3 heads and not more than 6 heads out of 10 tosses of a coin

P(3≤x≤6)=P(3)+P(4)+P(5)+P(6)

             =10C3+10C4+10C5+10C6

             =(10!/(7!*3!)+(10!/(6!*4!)+(10!/(5!*5!)+(10!/(4!*6!)

             =120+210+252+210

            =792

answered Sep 9, 2013 by bradely Mentor

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