find the inclination angle

Question

Find the inclination (in radians and degrees) of the line passing through the points.

(√3,2)(0,1)

Answer 1

The slope - intercept form is y = mx + b, m is slope and b is y-intercept The given points are (√3,2) (0,1) Slope formula is (y2-y1)/(x2-x1) Substitute the values in slope formula m = (1 - 2)⁄(0 - √3)                     ((x1,y1)=(√3,2)and(x2,y2) = (0,1)) m = -1⁄ - √3                              (Simplify) m = 1⁄ √3 The slope intercept form is y = 1⁄ √3 x + b Slope = 1⁄ √3 m =  1⁄ √3 Re call m = tanθ, where θ is inclination angle m = tanθ =1⁄ √3                    θ = 300 or -1200and 30 × ∏/180 θ = 300 or  -1200 and 30 × 3.14/180  θ = 300 or  -1200 and 0.52 (radians)              (Simplify) Since the slope is positive Tangent sign should be positive, so the line passes through the I and III quadrant. So, inclination angle is 300