please help in geometry

Question

ΔABC is a right triangle. m ∠A is 2° less than three times m ∠B. Find m ∠A and m ∠B, assuming ∠A is an acute angle.

Answer 1

ΔABC is a right triangle.

Assuming ∠A is an acute angle

m ∠A is 2° less than three times m ∠B, then 3m ∠B - 2° = m ∠A

∠C is right angle then m∠A+m∠B = 90°

3m∠B-2°+m∠B = 90°

4m∠B = 90-2

4m∠B = 88

m∠B = 88/4

m∠B = 22°

m∠A = 90-22 = 68°

 

Comments

Typo mistake in 6 th line of above solution.

4m∠B = 90+2

4m∠B = 92

m∠B = 92/4

m∠B = 23°

m∠A = 90 - 23 = 67°

Therfore, m∠B = 23° and m∠A =  67°.