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evaluate the integral

0 votes
x^3*sqrtx
asked Nov 8, 2013 in CALCULUS by linda Scholar

1 Answer

0 votes

imagex^3 sqrtx dx

=imagex^3*x^1/2 dx                                         a^m*a^n = a^m+n

=imagex^7/2 dx

= x^(7/2+1) / (7/2+1) +c                                       Recall the formula

= x^9/2/9/2 +c                                             imagex^n dx = x^n+1/n+1+c

=2/9 x^9/2+c

answered Nov 8, 2013 by william Mentor

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