Inverse of logarithmic function?

Question

Find the inverse to the logarithm log4 x+8

Answer 1

Given function log(base4)x+8

f(x) = log(base4)x+8

Start the function notation f(x) by y.

y = log(base4)x+8

Interchange the roles x and y.

x = log(base4)(y+8)

We know that log(base b)M =N then exponential functon is M = b^N

x = log(base4)(y+8)

4^x = y+8

Subtract 8 from each side.

4^x-8 = y+8-8

4^x-8 = y

Replace the y variable y by the inverse notation f^-1(x).

f^-1(x) = 4^x-8