Given the domain {-5,2,6} what is the range for the relation 6x + 3y = 6?

Question

what do I do?

Answer 1

x value is half coordinate pair and y value is half coordinate pair of the intersection piont.

x values are domains of a function and y values are range of a function.

Given domain {-5,2,6} and relation 6x+3y = 6

Substitute the domain values to find range of given relation.

For x = -5 then 6(-5)+3y = 6

-30+3y = 6

Add 30 to each side.

-30+30+3y = 6+30

3y = 36

Divide to each sides by 3.

3y/3 = 36/3

y = 12

For x = 2 then 6(2)+3y = 6

12+3y = 6

Subtract 12 from each side.

12-12+3y = 6-12

3y = -6

Divide to each side by 3.

3y/3 = -6/3

y = -2

For x = 6 then 6(6)+3y = 6

36+3y = 6

Subtract 36 from each side.

36-36+3y = 6-36

3y = -30

Divide to each side by 3.

3y/3 = -30/3

y = -10

Now the set of range for the relation 6x+3y = 6 is {12,-2,-10}