Question

Solve the system:

z + 3x + y = 3

2x + 3y = 10

2y = 8

Answer 1

z+3x+y = 3 ---------> (1)

2x+3y = 10 ---------> (2)

2y = 8

Divide to each side by 2.

2y/2 = 8/2

⇒ y = 4

Substitute the value of y in equation (2).

2x+3*4 = 10

2x+12 = 10

Subtract 12 from each side.

2x+12-12 = 10-12

2x = -2

Divide to each side by 2.

2x/2 = -2/2

⇒ x = -1

Substitute the x,y in equation (1).

z+3*-1+4 = 3

z-3+4 = 3

z +1 = 3

z +1-1 =3-1

⇒ z = 2

Solution of given system is x = -1,y = 4, z = 2.