by the process of elimination how do u solve 3+2x-y=0 and -3-7y=10x

Question

3+2x-y=0 and -3-7y=10x solve for x and y by useing process of elimination

Answer 1

Given equation 3+2x-y = 0

Subtract 3 from each side.

3-3+2x-y = 0-3

2x-y = -3

Multiple to each side of above equation by 5.

10x-5y = -15 -------> (1)

And -3-7y = 10x

add 3 to each side.

-3+3-7y = 10x+3

-7y = 10x+3

Subtract 10x from each side.

-10x-7y = 10x-10x+3

-10x-7y = 3 -------> (2)

To eliminate the x value, add the equations (1) and(2).

10x-5y = -15

-10x-7y = 3

_________

-12y = -12

Divide to each side by negitive 12.

-12y/-12 = -12/-12

⇒ y = 1

Substitute the y value in (1).

10x-5*1 = -15

10x-5 = -15

add 5 to each side.

10x-5+5 = -15+5

10x = -10

Divide to each side by  10.

10x/10 = -10/10

⇒ x = -1

Solution x = -1, y = 1