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what is this trinomial factored 14r^3-23r^2+8r

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PLEASE HELP ME!!

asked Dec 3, 2013 in ALGEBRA 1 by payton Apprentice

1 Answer

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Given trinomial is 14r^3-23r^2+8r

Take common out r from given trinomial.

= r(14r^2-23r+8)

Now facorize the 14r^2-23r+8

= 14r^2-16r-7r+8

= 2r(7r-8)-1(7r-8)

= (2r-1)(7r-8)

Factoring of given trinomial is r(2r-1)(7r-8).

answered Dec 4, 2013 by william Mentor

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