Question

Find the surface area of a right regular hexagonal pyramid with 2cm sides and 7cm slant height.  I've been trying to figure this out for days. I just don't get it.  Please help!

Answer 1

Calculate the surface area of a Regular Pyramid by using Formula : SA = (Pl)/2 + B, where P = perimeter of the base, B = area of the base and l = slant height.

Here the pyramid is regular hexagonal pyramid, so the base is hexagonal and its side is 2 cm and slant height is 7 cm.

The perimeter of the hexagonal P = 6a = 6(2) = 12 cm.

The area of the hexagonal A = (3√3 * a²)/2 = (3√3 * 2²)/2 = 10.39 cm².

Surface area of a Regular Pyramid : SA = (Pl)/2 + B.

SA = (12 * 7)/2 + 10.39

      = 42 + 10.39

      = 52.39 cm².