Welcome :: Homework Help and Answers :: Mathskey.com

Q&A
Unanswered
Categories
Users
Ask a Question

Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

Q&A Categories
BASIC MATH (93)
PRE-ALGEBRA (441)
ALGEBRA 1 (2,220)
GEOMETRY (864)
ALGEBRA 2 (2,751)
TRIGONOMETRY (1,187)
PRECALCULUS (1,903)
CALCULUS (2,802)
STATISTICS (129)
PHYSICS (659)
CHEMISTRY (137)
MECHANICAL ENGINEERING (64)
ELECTRICAL ENGINEERING (207)
Winplot Tutorials (2)

Most popular tags

solving-equations system-of-equations functions math slope-intercept-form physics homework-help trigonometric-identities integration limits substitution-method calculus

13,459 questions

17,854 answers

1,446 comments

805,810 users

sin^2xsec^2x=sec^2x–1

0 votes

Prove the trig identity.

trigonometric-identities

asked Feb 18, 2014 in TRIGONOMETRY by andrew Scholar

Share this question

Google+ Facebook Twitter LinkedIn Reddit

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 votes

Left hand side identity =

= Sin^2x Sec^2x

= (1-Cos^2x)Sec^2x

= Sec^2x-Cos^2x Sec^2x

= Sec^2x-Cos^2x/Cos^2x

= Sec^2x-1

= Right hand side identity

answered Feb 18, 2014 by david Expert

Please log in or register to add a comment.

Related questions

How do you verify that cos^2x(sec^2x-1)=sin^2x?

asked May 1, 2014 in ALGEBRA 2 by anonymous

trigonometric-identities

1/sec x tan x=csc x-sin x

asked Apr 15, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

Tan s / 1 + cos s + sin s / 1 - cos s = cot s + sec s csc s

asked Nov 30, 2013 in TRIGONOMETRY by chrisgirl Apprentice

trigonometric-identities

Sin (x-y) = 1-cot x tan y/csc x sec y?

asked Jan 9, 2013 in TRIGONOMETRY by homeworkhelp Mentor

trigonometric-identities

how can you prove: 1/cot^2x+secxcosx=sec^2x

asked Nov 30, 2013 in TRIGONOMETRY by rockstar Apprentice

trigonometric-identities

Verify the identity: cos x + sin x tan x = sec x.

asked Nov 20, 2013 in TRIGONOMETRY by andrew Scholar

trigonometric-identities

If sinx + sin^2x=1,

asked Jun 11, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

cos^4x - sin^4x = 1-2sin^2x

asked Feb 24, 2014 in TRIGONOMETRY by futai Scholar

trigonometric-identities

cos2x = 2-sec^2x/sec^2x

asked Mar 10, 2014 in TRIGONOMETRY by rockstar Apprentice

trigonometric-identities
solve-trigonometric-equations

How do i solve the double angle identity proof 2csc^2x = sec^2xcotx

asked Nov 26, 2013 in TRIGONOMETRY by dkinz Apprentice

double-angle-identities
trigonometric-identities

Verify the identity: (sinx + tanx + tan^3x)/tanx = cosx + sec^2x

asked Nov 20, 2013 in TRIGONOMETRY by homeworkhelp Mentor

trigonometric-identities

prove that tan theta/sec theta-1 = sec theta + 1/tan theta

asked Nov 30, 2013 in TRIGONOMETRY by abstain12 Apprentice

trigonometric-identities

cosx(secx-cosx)=sin^2x

asked Nov 30, 2013 in TRIGONOMETRY by payton Apprentice

trigonometric-identities

Prove cos^6x-sin^6x=cos2x-1/8sin4xsin2x?

asked Aug 22, 2015 in TRIGONOMETRY by anonymous

trigonometric-identities

solve: 2(sin^4x + cos^4x) = 1

asked Mar 8, 2014 in TRIGONOMETRY by rockstar Apprentice

trigonometric-identities
solve-trigonometric-equations

verify that that square root of (1-cos(x)/1+cox(x)) = sin(x)/1+cox(x)

asked Dec 5, 2013 in TRIGONOMETRY by chrisgirl Apprentice

trigonometric-identities

if sinθ = 1/2(x+1/x), show that sin 3θ + 1/2 (x^3 + 1/x^3) = 0

asked Nov 30, 2013 in TRIGONOMETRY by skylar Apprentice

trigonometric-identities

Prove that (1 - sin 2A)/(1 + sin 2A) = (1 - tan A)/(1 + tan A)

asked Nov 30, 2013 in TRIGONOMETRY by angel12 Scholar

trigonometric-identities

solve sinxcos(π/6) + sin(π/6)cosx= 1/√2

asked Nov 20, 2013 in TRIGONOMETRY by payton Apprentice

trigonometric-identities

verify the identity of sin^2(x)=1/2(1-cos2x)

asked Nov 20, 2013 in TRIGONOMETRY by chrisgirl Apprentice

trigonometric-identities

Copyright © 2024 MATHSKEY. All Rights Reserved. Sitemap|Terms Of Use|Disclaimer|Contact Us|FAQ

...