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sin^2xsec^2x=sec^2x–1

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Prove the trig identity.

trigonometric-identities

asked Feb 18, 2014 in TRIGONOMETRY by andrew Scholar

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1 Answer

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Left hand side identity =

= Sin^2x Sec^2x

= (1-Cos^2x)Sec^2x

= Sec^2x-Cos^2x Sec^2x

= Sec^2x-Cos^2x/Cos^2x

= Sec^2x-1

= Right hand side identity

answered Feb 18, 2014 by david Expert

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