given: y=arccos(4x) a)find the equation of the line tangent to the curve at x=1/8

Question

also,b) find the equation of the line normal to the curve at x=1/8

step by step and explanation of work tahnks alot .

Answer 1

a) The expression is

At

Differentiating above equation with recept to x.

The tangent line to the curve at .

The equation of the line tangent and the point .

The point -slope form of equation of a line :  , where m = slope.

The equation is 

Answer 2

b) The expression is

The expression is

At

Differentiating above equation with recept to x.

The normal line to the curve at .

The equation of the normal line  and the point .

The point -slope form of equation of a line :  , where m = slope.

The equation is .

 

Comments

Sorry, type of mistake

The equation of the normal line  and the point .

The point -slope form of equation of a line :  , where m = slope.

The equation is