determine whether each -value is a solution (or an approximate solution) of the equation.

Question

Equation : 2^(3x+1)=32

(a)  x = -1

(b) x = 2

Answer 1

The equation is 2^(3x+1)=32.

(a) Substitute the value of x = - 1 in 2^(3x+1) = 32.

2^[3(-1)+1] = 32

2^[-3+1] = 32

2^[-2] = 32

1/(2^2) = 32

1/4 = 32.

This is false.So, the x = - 1 is not a solution.

Answer 2

(b) Substitute the value of x = 2 in the original equation, 2^(3x+1)=32.

2^[3(2)+1] = 32

2^[6+1] = 32

2^[7] = 32

128 = 32.

This is false.So, the x = 2 is not a solution.